CINCINNATI — For the second time this season, Bengals quarterback Joe Burrow was named AFC Offensive Player of the Week.
What You Need To Know
- Joe Burrow won the AFC Offensive Player of the Week for Week 16
- He threw for 525 yards in a win versus the Ravens
- It is the second time Burrow has won the award in 2021
Burrow received the award for his performance in Cincinnati’s Week 16 win versus AFC North rival Baltimore. Cincinnati defeated the Ravens, 41-21, to stand alone in first place in the division.
No doubt about it.
— Cincinnati Bengals (@Bengals) December 29, 2021
Your AFC Offensive Player of the Week is @JoeyB. pic.twitter.com/figx2rmW3A
Burrow completed 37 of 46 pass attempts for 525 yards, 4 touchdowns and no interceptions.
His 525 yards were enough for fourth place all time for passing yards in a game in the NFL.
THE FOURTH MOST PASSING YARDS IN A GAME IN NFL HISTORY https://t.co/b5rKs0Wfyc
— Cincinnati Bengals (@Bengals) December 26, 2021
Burrow also won the award in Week 4 when the Bengals defeated the Jacksonville Jaguars, 24-21.
It is the sixth time a Bengals player has been named the conference player of the week in 2021.
The winners include:
Week 1 — Evan McPherson, K
Week 4 — Joe Burrow, QB
Week 7 — Ja’Marr Chase, WR
Week 11 — Evan McPherson, K
Week 12 — Joe Mixon, RB
Week 16 — Joe Burrow, QB
Burrow also won the FedEx Air Player of the Week, an award decided by fan vote. He also won the award in weeks 7 and 4.
The Bengals next host the Kansas City Chiefs at Paul Brown Stadium in the team’s home finale Jan. 2 at 1 p.m.